Two very long, straight, parallel conductors A and B carry current of 5 ~A and 10 ~A respectively and are at a distance of 10 ~cm from each other. The direction of current in two conductors is same. The force acting per

Correct answer: C. 1 × 10^ -4 Nm^ -1 and is attractive As per question, aligned F l & = μ_ o 4 π × 2 I_1 I_2 r & = 4 π × 10^ -7 × 2 × 5 × 10 2 π × 0.1 & =10^ -4 Nm^ -1 aligned The nature of the force is attractive. (where, the symbols have their usual meanings)

NEET 2022

Exam: NEET
Year: 2022
Subject: Physics
Chapter: Magnetic Effects of Current

NEET 2022 · Physics · Magnetic Effects of Current

Two very long, straight, parallel conductors A and B carry current...

Two very long, straight, parallel conductors A and

\mathrm{B}

carry current of

5 \mathrm{~A} and 10 \mathrm{~A}

respectively and are at a distance of

10 \mathrm{~cm}

from each other. The direction of current in two conductors is same. The force acting per unit length between two conductors is

\left(\mu_0=4 \pi \times 10^{-7}\right.

SI unit):

Options

A $2 \times 10^{-4} \mathrm{Nm}^{-1}$ and is attractive
B $2 \times 10^{-4} \mathrm{Nm}^{-1}$ and is repulsive
C $1 \times 10^{-4} \mathrm{Nm}^{-1}$ and is attractive
D $1 \times 10^{-4} \mathrm{Nm}^{-1}$ and is repulsive

Correct answer

C. $1 \times 10^{-4} \mathrm{Nm}^{-1}$ and is attractive

Step-by-step solution

As per question,

\begin{aligned} \frac{\mathrm{F}}{l} & =\frac{\mu_{\mathrm{o}}}{4 \pi} \times \frac{2 \mathrm{I}_1 \mathrm{I}_2}{r} \\ & =\frac{4 \pi \times 10^{-7} \times 2 \times 5 \times 10}{2 \pi \times 0.1} \\ & =10^{-4} \mathrm{Nm}^{-1} \end{aligned}

The nature of the force is attractive. (where, the symbols have their usual meanings)

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