A soap bubble having radius of 1mm is blown from a detergent...

Pressure inside soap bubble is given by, $\text{∆}P = \dfrac{4T}{R}$
Pressure below water surface at depth ${Z}_{0}$ is given by, $∆ P = ρg{Z}_{0}$
According to question,
$⇒ \dfrac{4T}{R} = ρg{Z}_{0}$
$⇒ {Z}_{0} = \dfrac{4T}{ρg} = \dfrac{4 \times 2.5 \times {10}^{- 2}}{{10}^{3} \times 10 \times {10}^{- 3}}$
$⇒ {Z}_{0} = \dfrac{1}{100}m$
$⇒ {Z}_{0} = 1cm$