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NEET 2023
Exam
NEET
Year
2023
Subject
Physics
Chapter
Ray Optics

NEET 2023 · Physics · Ray Optics

Light travels a distance x in time t _ 1 in air and 10x in time t _...

Light travels a distancexxin timet1{t}_{1} in air and 10x10x in time t2{t}_{2} in another denser medium. What is the critical angle for this medium?

Options

  1. Asin⁡−1(10t1t2)\sin^{- 1} ( \dfrac{10{t}_{1}}{{t}_{2}} )
  2. Bsin⁡−1(t2t1)\sin^{- 1}\left(\dfrac{{t}_{2}}{{t}_{1}}\right)
  3. Csin⁡−1(10t2t1)\sin^{- 1}\left(\dfrac{10{t}_{2}}{{t}_{1}}\right)
  4. Dsin⁡−1(t110t2)\sin^{- 1}\left(\dfrac{{t}_{1}}{10{t}_{2}}\right)

Correct answer

A. sin⁡−1(10t1t2)\sin^{- 1} ( \dfrac{10{t}_{1}}{{t}_{2}} )

Step-by-step solution

Applying Snell's law for refraction from denser to rarer medium, we get

μdenser\timessinC=μair\timessin90°⇒cvdenser{μ}_{denser} \timessinC = {μ}_{air} \timessin90 ° ⇒\dfrac{c}{vdenser}sinC=cvair×1⇒c10xt2sinC=cxt1⇒sinC=10t1t2⇒C=sin⁡−1(10t1t2)</p></blockquote>inC =\dfrac{c}{vair}\times1 ⇒ \dfrac{c}{\dfrac{10x}{t2}}sinC = \dfrac{c}{\dfrac{x}{t1}}⇒ sinC = \dfrac{10{t}_{1}}{t2}⇒ C = \sin^{- 1} \left(\dfrac{10{t}_{1}}{t2}\right)</p></blockquote>

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