NEET2020PhysicsRay OpticsActual
The power of a biconvex lens is 10 dioptre and the radius of curvature of each surface is 10   cm . Then the refractive index of the material of the lens is,
Options
- A4 3
- B9 8
- C5 3
- D3 2
Correct answer
D. 3 2
Step-by-step solution
Recall the proper relation between power and focal length, P = 100 f ⇒ f = 100 P = 100 10 = 10   cm , now the relation between focal length and radius of curvature and refractive index, of the spherical surface lens, f = R 2 ( μ - 1 ) (for equiconvex lens) ⇒ 10 = 10 2 ( μ - 1 ) ⇒ ( μ - 1 ) = 1 2 ⇒ μ = 1 2 + 1 = 3 2 .