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NEET 2011
Exam
NEET
Year
2011
Subject
Physics
Chapter
Ray Optics

NEET 2011 · Physics · Ray Optics

A biconvex lens has a radius of curvature of magnitude 20 ~cm ....

A biconvex lens has a radius of curvature of magnitude 20 cm20 \mathrm{~cm}. Which one of the following options describe best the image formed of an object of height 2 cm2 \mathrm{~cm} placed 30 cm30 \mathrm{~cm} from the lens?

Options

  1. AVirtual, upright, height =0.5 cm=0.5 \mathrm{~cm}
  2. BReal, inverted, height =4 cm=4 \mathrm{~cm}
  3. CReal, inverted, height =1 cm=1 \mathrm{~cm}
  4. DVirtual, upright, height =1 cm=1 \mathrm{~cm}

Correct answer

B. Real, inverted, height =4 cm=4 \mathrm{~cm}

Step-by-step solution

In general we have assumed μ=1.5\mu=1.5 So, f=20cmf=20 \mathrm{ cm}1f=1y+1u120=1y+1301y=120−130=10600y=60cmhih0=2hi=2×∣hohi=4cm\begin{aligned}\frac{1}{f}& =\frac{1}{y}+\frac{1}{u}\\ \frac{1}{20}& =\frac{1}{y}+\frac{1}{30}\\ \frac{1}{y}& =\frac{1}{20}-\frac{1}{30}=\frac{10}{600}\\ y & =60 \mathrm{ cm}\\ \frac{h_i}{h_0}& =2 \\ h_i & =2 \times \mid h_o \\ h_i & =4 \mathrm{ cm} \end{aligned}$Here,Imageisreal,inverted,magnifiedfieldandheightofimageisHere, Image is real, inverted, magnified field and height of image is4 \mathrm{ cm}$.
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