A thin prism of angle 15^ made of glass of refractive index μ_1=1.5 is combined with another prism of glass of refractive index μ_2=1.75 . The combination of the prism produces dispersion without deviation. The angle of

Correct answer: B. 10^ For without deviation aligned A A^ & = μ^ -1 μ-1 15^ ^ A^ & =(1.75-1)/(1.5-1) 15 A^ & =(0.75)/(0.50) A^ & =(0.50 × 15)/(0.75)=10^ ^ aligned

NEET 2011

Exam: NEET
Year: 2011
Subject: Physics
Chapter: Ray Optics

NEET 2011 · Physics · Ray Optics

A thin prism of angle 15^ made of glass of refractive index μ_1=1.5...

A thin prism of angle

15^{\circ}

made of glass of refractive index

\mu_1=1.5

is combined with another prism of glass of refractive index

\mu_2=1.75

. The combination of the prism produces dispersion without deviation. The angle of the second prism should be

Options

A $7^{\circ}$
B $10^{\circ}$
C $12^{\circ}$
D $5^{\circ}$

Correct answer

B. $10^{\circ}$

Step-by-step solution

For without deviation

\begin{aligned}\frac{A}{A^{\prime}}& =\frac{\mu^{\prime}-1}{\mu-1}\\ \frac{15^{{}^{\circ}}}{A^{\prime}}& =\frac{1.75-1}{1.5-1}\\ \frac{15}{A^{\prime}}& =\frac{0.75}{0.50}\\ A^{\prime} & =\frac{0.50 \times 15}{0.75}=10^{{}^{\circ}} \end{aligned}

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