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NEET 2025
Exam
NEET
Year
2025
Subject
Physics
Chapter
Ray Optics

NEET 2025 · Physics · Ray Optics

A microscope has an objective of focal length 2 cm , eyepiece of...

A microscope has an objective of focal length 2 cm , eyepiece of focal length 4 cm and the tube length of 40 cm . If the distance of distinct vision of eye is 25 cm , the magnification in the microscope is :

Options

  1. A100100
  2. B125125
  3. C150150
  4. D250250

Correct answer

B. 125125

Step-by-step solution

f0=2 cmfe=4 cm L=40 cmD=25 cm\begin{array}{ll} \mathrm{f}_0=2 \mathrm{~cm} & \mathrm{f}_e=4 \mathrm{~cm} \\ \mathrm{~L}=40 \mathrm{~cm} & \mathrm{D}=25 \mathrm{~cm} \end{array} In the condition of normal adjustment. m=Lf0⋅Dfe=402×254=125\begin{aligned} \mathrm{m} & =\frac{\mathrm{L}}{\mathrm{f}_0} \cdot \frac{\mathrm{D}}{\mathrm{f}_e} \\ & =\frac{40}{2} \times \frac{25}{4} \\ & =125 \end{aligned}
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