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NEET 2012
Exam
NEET
Year
2012
Subject
Physics
Chapter
Ray Optics

NEET 2012 · Physics · Ray Optics

A rod of length 10 ~cm lies along the principal axis of a concave...

A rod of length 10 cm10 \mathrm{~cm} lies along the principal axis of a concave mirror of focal length 10 cm10 \mathrm{~cm} in such a way that its end closer to the pole is 20 cm20 \mathrm{~cm} away from the mirror. The length of the image isA rod of length 10 ~cm lies along the principal axis of a concave mirror of focal length 10 ~cm in such a way that itsA rod of length 10 ~cm lies along the principal axis of a concave mirror of focal length 10 ~cm in such a way that its

Options

  1. A10 cm10 \mathrm{~cm}
  2. B15 cm15 \mathrm{~cm}
  3. C2.5 cm2.5 \mathrm{~cm}
  4. D5 cm5 \mathrm{~cm}

Correct answer

D. 5 cm5 \mathrm{~cm}

Step-by-step solution

By mirror formula, image distance of A 1v+1u=1f\frac{1}{v}+\frac{1}{u}=\frac{1}{f}A rod of length 10 ~cm lies along the principal axis of a concave mirror of focal length 10 ~cm in such a way that its\\1vA+1u=1f1vA+1(−30)=1−10vA=−15 cm\begin{aligned}\frac{1}{v_A}+\frac{1}{u}& =\frac{1}{f}\\ \frac{1}{v_A}+\frac{1}{(-30)}& =\frac{1}{-10}\\ v_A & =-15 \mathrm{~cm}\end{aligned}AlsoimagedistanceAlso image distance of C$ v_C=-20 \mathrm{~cm}The length of image =\left|v_A-v_C\right| =|-15-(-20)| =5 \mathrm{~cm}
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