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NEET 2024
Exam
NEET
Year
2024
Subject
Physics
Chapter
Rotational Motion

NEET 2024 · Physics · Rotational Motion

The radius of gyration of a solid sphere of mass 5 kg about X Y is...

The radius of gyration of a solid sphere of mass 5 kg about XYX Y is 5 m as shown in figure. The radius of the sphere is 5x7 m\frac{5 x}{\sqrt{7}} \mathrm{~m}, then the value of xx is: The radius of gyration of a solid sphere of mass 5 kg about X Y is 5 m as shown in figure. The radius of the sphere is

Options

  1. A5
  2. B2\sqrt{2}
  3. C2\sqrt{2}
  4. D5\sqrt{5}

Correct answer

D. 5\sqrt{5}

Step-by-step solution

IXY=ICM+MR2=25MR2+MR2=75MR2=75×5R2=7R2I_{X Y}=I_{C M}+M R^2=\frac{2}{5} M R^2+M R^2=\frac{7}{5} M R^2=\frac{7}{5} \times 5 R^2=7 R^2...(1) IXY=MK2=5×52I_{X Y}=M K^2=5 \times 5^2...(ii) ∴5×52=7×R2[\therefore 5 \times 5^2=7 \times R^2 \quad[ From (1) and (2)] ⇒R=57×5=5x7\Rightarrow R=\sqrt{\frac{5}{7}} \times 5=\frac{5 x}{\sqrt{7}} \quad (Given) ∴x=5\therefore x=\sqrt{5}
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