The radius of gyration of a solid sphere of mass 5 kg about X Y is 5 m as shown in figure. The radius of the sphere is 5 x 7 ~m , then the value of x is:

Step-by-step solution

I_ X Y =I_ C M +M R^2= 2 5 M R^2+M R^2= 7 5 M R^2= 7 5 5 R^2=7 R^2 ...(1) I_ X Y =M K^2=5 5^2 ...(ii) 5 5^2=7 R^2 [ From (1) and (2)] R= 5 7 5= 5 x 7 (Given) x= 5