The angular speed of a flywheel is increased from 600 rpm to 1200 rpm in 10 s. The number of revolutions completed by the flywheel during this time is :

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Correct answer: C. 150

Initial angular speed, ω_0 = (600 × 2π)/(60) = 20π rad/s Final angular speed, ω = (1200 × 2π)/(60) = 40π rad/s Angular acceleration, α = (ω - ω_0)/(t) = (40π - 20π)/(10) = 2π rad/s ^2 Angular displacement, θ = ω_0 t + (1)/(2)α t^2 θ = 20π × 10 + (1)/(2) × 2π × (10)^2 = 200π + 100π = 300π rad Number of revolutions, N = (θ)/(2π) = (300π)/(2π) = 150 Answer: 150

The angular speed of a flywheel is increased from 600 rpm to 1200...

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