NEET2009PhysicsThermal Properties of MatterActual
The two ends of a rod of length L and a uniform cross-sectional area A are kept at two temperatures T₁ and T₂ (T₁>T₂ ) . The rate of heat transfer, dQ dt , through the rod in a steady state is given by :
Options
- AdQ dt = kA ( T ₁- T ₂ ) L
- BdQ dt = kL ( T ₁- T ₂ ) A
- CdQ dt = k ( T ₁- T ₂ ) LA
- DdQ dt = kLA ( T ₁- T ₂ )
Correct answer
A. dQ dt = kA ( T ₁- T ₂ ) L
Step-by-step solution
For steady state dQ dt = kA ( T ₁- T ₂ ) L