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NEET 2008
Exam
NEET
Year
2008
Subject
Physics
Chapter
Thermal Properties of Matter

NEET 2008 · Physics · Thermal Properties of Matter

On a new scale of temperature (which is linear) and called the W...

On a new scale of temperature (which is linear) and called the W scale, the freezing and boiling points of water are 39∘W39^{\circ} \mathrm{W} and 239∘W239^{\circ} \mathrm{W} respectively. What will be the temperature on the new scale, corresponding to a temperature of 39∘C39^{\circ} \mathrm{C} on the Celsius scale?

Options

  1. A139∘W139^{\circ} \mathrm{W}
  2. B78∘W78^{\circ} \mathrm{W}
  3. C117∘W117^{\circ} \mathrm{W}
  4. D200∘W200^{\circ} \mathrm{W}

Correct answer

C. 117∘W117^{\circ} \mathrm{W}

Step-by-step solution

39−0100−0=x−39239−39⇒x=117∘W\begin{aligned}& \frac{39-0}{100-0}=\frac{x-39}{239-39}\\ & \Rightarrow \quad x=117^{{}^{\circ}} \mathrm{W} \end{aligned}
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