The two ends of a metal rod are maintained at temperatures 100 ° C and 110 ° C . The rate of heat flow in the rod is found to be 4.0 J s - 1 . If the ends are maintained at temperatures 200 ° C and 210 ° C , the rate of heat flow will be:

Step-by-step solution

In case I, temperature difference between the ends of rod is = 110 - 100 = 10 o C In case II, temperature difference between the ends of rod is = 210 - 200 = 10 o C Hence, in both the case temperature difference are same i.e. 10 o C ∴ Rate of heat flow is also 4   J   s - 1 in both the cases.