NEET2003PhysicsThermal Properties of MatterActual
Consider a compound slab consisting of two different materials having equal thickness and thermal conductivities K and 2 K , respectively. The equivalent thermal conductivity of the slab is:
Options
- A4 3 K
- B2 K
- C3 ~K
- D2 3 K
Correct answer
A. 4 3 K
Step-by-step solution
2 l K_ e g (A) = l 2 K A + l K A for series connection R = R ₁+ P ₂ K_ e g = 4 3 K