NEET2002PhysicsThermal Properties of MatterActual
Consider two rods of the same length and different specific heats (S₁, S₂ ) , conductivities (K₁, K₂ ) and area of cross sections (A₁, A₂ ) and both having temperature T₁ and T₂ at their ends. If the rate of loss of heat due to conduction is equal then:
Options
- AK₁ A₁=K₂ A₂
- BK₁ A₁ S₂ = K₂ A₂ S₁
- CK₂ A₁=K₁ A₂
- DK₂ A₁ S₂ = K₁ A₂ S₁
Correct answer
A. K₁ A₁=K₂ A₂
Step-by-step solution
Rate of conduction of heat is given as Q t = K A L (T₂-T₁ ) According to the question aligned & Q₁ t = Q₂ t & K₁ A₁ L (T₁-T₂ )= K₁ A₁ L (T₁-T₂ ) & K₁ A₁=K₂ A₂ aligned