NEET2009PhysicsThermal Properties of MatterActual
The two ends of a rod of length L and a uniform cross-sectional area A are kept at two temperatures T ₁ and T ₂ ( ~T ₁> T ₂ ) . The rate of heat transfer, dQ dt , through the rod in a steady state is given by
Options
- AdQ dt = KL ( T ₁- T ₂ ) A
- BdQ dt = K ( T ₁- T ₂ ) LA
- CdQ dt = KLA ( T ₁- T ₂ )
- DdQ dt = KA ( T ₁- T ₂ ) L
Correct answer
D. dQ dt = KA ( T ₁- T ₂ ) L
Step-by-step solution
For a rod of length L and area of cross-section A whose faces are maintained at temperature T ₁ and T ₂ respectively. Then in steady state the rate of heat flowing from one face to the other face in time t is given by dQ dt = KA ( T ₁- T ₂ ) L The curved surface of rod is kept insulated from surrounding to avoid leakage of heat.