One mole of an ideal monatomic gas undergoes a cyclic process as shown in the figure. The total heat supplied to the gas is :

Step-by-step solution

For a complete cyclic process, the change in internal energy is zero, i.e., U = 0 . According to the first law of thermodynamics, Q = U + W . Therefore, the net heat supplied to the gas is equal to the net work done by the gas: Q = W . The net work done W is given by the area enclosed by the cycle on the P-V diagram. W = Area of rectangle abcd W = (P_a - P_d) (V_b - V_a) W = (300 - 100) (5 - 2) W = 200 3 = 600 J Thus, the total heat supplied to the gas is 600 J . Answer: 600 J