A Carnot's engine having an efficiency of 1 10 as heat engine, is used as a refrigerator. If the work done on the system is 10 J, the amount of energy absorbed from the reservoir at lower temperature is

Step-by-step solution

β = coefficient of performance of refrigerator η = efficiency of heat engine β = 1 - η η = 1 - 1 10 1 10 = 9 10 1 10 β = 9 β = Q 2 W ∵ Q 2 = heat absorbed from sink and W = work done in a cycle Q 2 = 9 × 10 = 90 J