A Carnot's engine having an efficiency of (1)/(10) as heat engine, is used as a refrigerator. If the work done on the system is 10 J, the amount of energy absorbed from the reservoir at lower temperature is

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Correct answer: B. 90J

β = coefficient of performance of refrigerator η = efficiency of heat engine β = (1 - η)/(η) = (1 - (1)/(10))/((1)/(10)) = ((9)/(10))/((1)/(10)) β = 9 β = Q _ 2 W ∵ Q _ 2 = heat absorbed from sink and W = work done in a cycle Q _ 2 = 9 × 10 = 90J

A Carnot's engine having an efficiency of (1)/(10) as heat engine,...

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