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NEET 2016

Exam: NEET
Year: 2016
Subject: Physics
Chapter: Thermodynamics

NEET 2016 · Physics · Thermodynamics

The temperature inside a refrigerator is t _ 2 ^ o C and the room...

The temperature inside a refrigerator is

{t}_{2}{}^{o}C

and the room temperature is

{t}_{1}{}^{o}C

. The amount of heat delivered to the room for each joule of electrical energy consumed ideally will be

Options

A $\dfrac{{t}_{1}}{{t}_{1} - {t}_{2}}$
B $\dfrac{{t}_{1} + 273}{{t}_{1} - {t}_{2}}$
C $\dfrac{{t}_{2} + 273}{{t}_{1} - {t}_{2}}$
D $\dfrac{{t}_{1} + {t}_{2}}{{t}_{1} + 273}$

Correct answer

B. $\dfrac{{t}_{1} + 273}{{t}_{1} - {t}_{2}}$

Step-by-step solution

$K = \dfrac{{Q}_{2}}{W} = \dfrac{1}{\dfrac{{t}_{1}}{{t}_{2}} - 1}$

${Q}_{2} = \dfrac{{t}_{2}W}{{t}_{1} - {t}_{2}}$ .

${Q}_{1} = {Q}_{2} + W = \dfrac{{t}_{2}W}{{t}_{1} - {t}_{2}} + W$

$= \dfrac{{t}_{1}W}{{t}_{1} - {t}_{2}}$ .

Since, ${t}_{1} \text{ and } {t}_{2}$ are in $oC \text{ and } W=1J$ ,

${Q}_{1} = \dfrac{{t}_{1} + 273}{{t}_{1} - {t}_{2}}$ .

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