In an adiabatic expansion, the temperature of one mole of an ideal monatomic gas ( =5/3 ) decreases from 60 K to 50 K. The work done by the gas in the process is : (Take the universal gas constant as R=8.3 J mol ⁻¹ K ⁻¹ )

Step-by-step solution

The work done by an ideal gas in an adiabatic process is given by the formula: W = nR(T₁ - T₂) - 1 Given values are: n = 1 mole R = 8.3 J mol ⁻¹ K ⁻¹ T₁ = 60 K T₂ = 50 K = 5 3 Substituting these values into the formula: W = 1 8.3 (60 - 50) 5 3 - 1 W = 8.3 10 2 3 W = 83 3 2 W = 249 2 = 124.5 J Answer: 124.5 J