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NEET 2012
Exam
NEET
Year
2012
Subject
Physics
Chapter
Thermodynamics

NEET 2012 · Physics · Thermodynamics

A thermodynamic system is taken through the cycle A B C D as shown...

A thermodynamic system is taken through the cycle ABCDA B C D as shown in figure. Heat rejected by the gas during the cycle is A thermodynamic system is taken through the cycle A B C D as shown in figure. Heat rejected by the gas during the cycle

Options

  1. A2pV2 \mathrm{pV}
  2. B4pV4 p V
  3. C12pV\frac{1}{2} p V
  4. DpVp V

Correct answer

A. 2pV2 \mathrm{pV}

Step-by-step solution

For given cyclic process, ΔU=0∴Q=W\Delta U=0 \therefore Q=W Also, W=−W=- area enclosed by the curve =AB×AD=(2p−p)(3V−V)=−p×2V\begin{aligned} & =A B \times A D \\ & =(2 p-p)(3 V-V) \\ & =-p \times 2 V \end{aligned}\thereforeHeatrejectedHeat rejected=2 p_V$
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