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NEET 2011
Exam
NEET
Year
2011
Subject
Physics
Chapter
Thermodynamics

NEET 2011 · Physics · Thermodynamics

When 1 ~kg of ice at 0^ C melts to water at 0^ C , the resulting...

When 1 kg1 \mathrm{~kg} of ice at 0∘C0^{\circ} \mathrm{C} melts to water at 0∘C0^{\circ} \mathrm{C}, the resulting change in its entropy, taking latent heat of ice to be 80cal/∘C80 \mathrm{cal} /{ }^{\circ} \mathrm{C}, is

Options

  1. A8×104cal/K8 \times 10^4 \mathrm{cal} / \mathrm{K}
  2. B80cal/K80 \mathrm{cal} / \mathrm{K}
  3. C293cal/K293 \mathrm{cal} / \mathrm{K}
  4. D273cal/K273 \mathrm{cal} / \mathrm{K}

Correct answer

C. 293cal/K293 \mathrm{cal} / \mathrm{K}

Step-by-step solution

Change in entroy Δ\DeltaS=ml273 T=1000×80273=\frac{m l}{273 \mathrm{~T}}=\frac{1000 \times 80}{273}=293 calK−1\mathrm{cal} \mathrm{K}^{-1}
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