An ideal gas goes from state A to state B via three different...

An ideal gas goes from state

A

to state

B

via three different processes as indicated in the

p-V

diagram If

Q_1, Q_2, Q_3

indicate the heat absorbed by the gas along the three processes and

\Delta U_1, \Delta U_2, \Delta U_3

indicate the change in internal energy along the three processes respectively, then An ideal gas goes from state A to state B via three different processes as indicated in the p-V diagram If Q_1, Q_2,

An ideal gas goes from state A to state B via three different processes as indicated in the p-V diagram If Q_1, Q_2,

Options

A $Q_1>Q_2>Q_3$ and $\Delta U_1=\Delta U_2=\Delta U_3$
B $Q_3>Q_2>Q_1$ and $\Delta U_1=\Delta U_2=\Delta U_3$
C $Q_1=Q_2=Q_3$ and $\Delta U_1>\Delta U_2>\Delta U_3$
D $Q_3>Q_2>Q_1$ and $\Delta U_1>\Delta U_2>\Delta U_3$

Correct answer

A. $Q_1>Q_2>Q_3$ and $\Delta U_1=\Delta U_2=\Delta U_3$

Step-by-step solution

For all process 1,2 and 3

\begin{array}{ll} & \Delta U=U_B-U_A \text{ is same } \\ \therefore & \Delta U_1=\Delta U_2=\Delta U_3 \\ \text{ Now, } & \Delta Q=\Delta U+\Delta W \end{array}

Now,

\Delta W=

work done by the gas \therefore \quad \Delta Q_1>\Delta Q_2>\Delta Q_3

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