NEET2011PhysicsThermodynamicsActual
A mass of diatomic gas ( =1.4) at a pressure of 2 ~atm is compressed adiabatically so that its temperature rise from 27^ C to 927^ C . The pressure of the gas is final state is
Options
- A28 ~atm
- B68.7 ~atm
- C256 ~atm
- D8 ~atm
Correct answer
C. 256 ~atm
Step-by-step solution
aligned & T₁=273+27=300 ~K & T₂=273+927=1200 ~K aligned Gas equation for adiabatic process aligned & p V^ = constant & p ( T p )^ = constant ( p V=R T) & p₂ p₁ = ( T₂ T₁ )^ -1 & p₂=p₁ ( T₂ T₁ )^ -1 & p₂=2 ( 1200 300 )^ 1.4 1.4-1 & p₂=256 ~atm aligned