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NEET 2009
Exam
NEET
Year
2009
Subject
Physics
Chapter
Thermodynamics

NEET 2009 · Physics · Thermodynamics

The internal energy change in a system that has absorbed 2 k cal of...

The internal energy change in a system that has absorbed 2k2 \mathrm{k} cal of heat and done 500 J500 \mathrm{~J} of work is :

Options

  1. A7900 J7900 \mathrm{~J}
  2. B8900 J8900 \mathrm{~J}
  3. C6400 J6400 \mathrm{~J}
  4. D5400 J5400 \mathrm{~J}

Correct answer

A. 7900 J7900 \mathrm{~J}

Step-by-step solution

dU=Q−W=8400−500=7900 J\mathrm{dU}=\mathrm{Q}-\mathrm{W}=8400-500=7900 \mathrm{~J}
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