If E and G respectively denote energy and gravitational constant,...

Dimensional Formulas,

Energy, $[ E ] = {M}^{1}{L}^{2}{T}^{- 2}$

Gravitational constant

$[ G ] = \left[\dfrac{F{r}^{2}}{{M}^{2}}\right] = \dfrac{{M}^{1}{L}^{1}{T}^{- 2} \times {L}^{2}}{{M}^{2}}$

$[ G ] = {M}^{- 1}{L}^{3}{T}^{- 2}$

Now,

\left[\dfrac{E}{G}\right] = \dfrac{M{L}^{2}{T}^{- 2}}{{M}^{- 1}{L}^{3}{T}^{- 2}} = {M}^{2}{L}^{- 1}{T}^{0}

Correct option (3)