NEET2016PhysicsWave OpticsActual
In a diffraction pattern due to a single slit of width a the first minimum is observed at an angle 30 o when light of wavelength 5000   Å is incident on the slit. The first secondary maximum is observed at an angle of:
Options
- Asin - 1 1 4
- Bsin - 1 2 3
- Csin - 1 1 2
- Dsin - 1 3 4
Correct answer
D. sin - 1 3 4
Step-by-step solution
a sin ⁡ 30 = λ a sin ⁡ θ = 3 λ 2 sin ⁡ θ sin ⁡ 30 = 3 2 sin ⁡ θ = 3 2 × 1 2 sin ⁡ θ = 3 4 θ = sin ⁡ 3 4