NEET2014PhysicsWaves and SoundActual
If n 1 ,   n 2 and n 3 are the fundamental frequencies of three segments into which a string is divided, then the original fundamental frequency n of the string is given by:
Options
- A1 n = 1 n 1 + 1 n 2 + 1 n 3
- B1 n = 1 n 1 + 1 n 2 + 1 n 3
- Cn = n 1 + n 2 + n 3
- Dn = n 1 + n 2 + n 3
Correct answer
A. 1 n = 1 n 1 + 1 n 2 + 1 n 3
Step-by-step solution
For first segment we have, n 1 = 1 2 l 1   T μ For second segment we have, n 2 = 1 2 l 2   T μ For third segment we have, n 3 = 1 2 l 3 T μ For the whole string we have, n = 1 2 l   T μ Total length of the string is, l = l 1 + l 2 + l 3 Thus, the fundamental frequency for the whole string is, 1 n = 1 n 1 + 1 n 2 + 1 n 3