Two source P and Q produce notes of frequency 660 ~Hz each. A listener moves from P to Q with a speed of 1 ~ms ⁻¹ . If the speed of sound is 330 ~m / s , then the number of beats heard by the listener per second will be:

Step-by-step solution

According to the question Speed of listener V_L=1 ~ms ⁻¹ Speed of sound V=330 ~ms ⁻¹ Frequency of each source v=600 ~Hz Apparent frequency due to P = V ^ = v ( ~V - V _ L ) V Apparent frequency due to Q = V ^ = v ( ~V - V _ L ) V No. of heat heard by the listener per second. aligned & V ^ - V ^ = v ( ~V - V _ L ) V - v ( ~V ₀- V _ L ) V & = 2 v_ L v = 2 660 1 330 =4 aligned