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NEET2010PhysicsWaves and SoundActual

A tuning fork of frequency 512 ~Hz makes 4 beats/seconds with the vibrating string of a piano. The beat frequency decreases to 2 beats/s when the tension in the piano string is slightly increased. The frequency of the piano string before increasing the tension was

Options

  1. A510 ~Hz
  2. B514 ~Hz
  3. C516 ~Hz
  4. D508 ~Hz

Correct answer

D. 508 ~Hz

Step-by-step solution

Suppose n_p= frequency of piano = ? (n_p T ) n _ f = frequency of tuning fork =512 ~Hz x = Beat frequency =4 beats / s , which is decreasing (4 2) after changing the tension of piano wire. Also, tension of piano wire is increasing so n_p Hence, n _ p - n _ f = x wrong n _ f - n _ p = x correjct n _ p = n _ f - x =512-4=508 ~Hz

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