. Two points are located at a distance of 10 ~m and 15 ~m from the source of oscillation. The period of oscillation is 0.05 sec and the velocity of the wave is 300 ~m / sec . What is the phase difference between the

Correct answer: C. (2 π)/(3) Phase difference φ=(2 π)/(λ) × path difference aligned & =(2 π)/(15) ×(15-10) \ λ=v T=300 ×0.05 ~m & =(2 π)/(5) aligned

NEET 2008

NEET 2008 · Physics · Waves and Sound

. Two points are located at a distance of 10 ~m and 15 ~m from the...

. Two points are located at a distance of

10 \mathrm{~m}

and

15 \mathrm{~m}

from the source of oscillation. The period of oscillation is

0.05 \mathrm{sec}

and the velocity of the wave is

300 \mathrm{~m} / \mathrm{sec}

. What is the phase difference between the oscillations of two points?

C. $\frac{2 \pi}{3}$

Phase difference

\phi=\frac{2 \pi}{\lambda} \times

path difference

\begin{aligned}& =\frac{2 \pi}{15} \times(15-10) \quad\{\lambda=v T=300 \times0.05 \mathrm{~m} \\ & =\frac{2 \pi}{5} \end{aligned}