The time of reverberation of a room A is one second. What will be the time (in seconds) of reverberation of a room, having all the dimensions double of those of room A ?

Step-by-step solution

Reverberation Time T= 0 61 V A S Where V= Volume of room in cubic metre A= Average coefficient of the room S= Total surface area of room Then, aligned & T V S & or T₁ T₂ = ( V₁ V₂ ) ( S₂ S₁ )= ( V 8 V ) ( 45 5 ) & = 1 2 & T₂=2 T₁=2 1=2 sec . & ( T₁=1 sec ) & aligned