The phase difference between two waves represented by aligned & y₁=10⁻⁶ [100 t+(x / 50)+0.5] m & y₁=10⁻⁶ [100 t+(x / 50)] m aligned where x is expressed in metres and t is expressed in seconds is approximately

Step-by-step solution

Here y₁=10^6 [100 t+ ( x 50 )+0.5 ] aligned & and y₂=10⁻⁶ [100 t+ ( x 50 ) ] & =10⁻⁶ [100 t+ ( x 50 )+ 2 ] & =10⁻⁶ [100 t+ ( x 50 )+1.57 ] aligned Then comparing the equation of y₁ and y₂ we get phase difference =1.57-0.5=1.07