A wave travelling in the positive x -direction with amplitude A=0.2 ~m , velocity v=360 ~ms^ -1 and wavelength λ =60 ~m , then the correct expression for the wave is:

Correct answer: C. y=0.2 [2 π(6 t-(x)/(60))] The general equation of wave travelling in x -direction is given as y=A [(2 π)/(λ)( V t-x)] Where A=0.2 ~m, v=360 ~ms^ -1 , λ=60 ~m The equation becomes aligned & y=0.2 [(2 π)/(60)(360 t-x)] & y=0.2 [2 π(6 t-(x)/(60))] aligned

NEET 2002

Exam: NEET
Year: 2002
Subject: Physics
Chapter: Waves and Sound

NEET 2002 · Physics · Waves and Sound

A wave travelling in the positive x -direction with amplitude A=0.2...

A wave travelling in the positive

x

-direction with amplitude

\mathrm{A}=0.2 \mathrm{~m}

, velocity

v=360 \mathrm{~ms}^{-1}

and wavelength

\lambda

=60 \mathrm{~m}

, then the correct expression for the wave is:

Options

A $y=0.2 \sin \left[2 \pi\left(6 t+\frac{x}{60}\right)\right]$
B $y=0.2 \sin \left[\pi\left(6 t+\frac{x}{60}\right)\right]$
C $y=0.2 \sin \left[2 \pi\left(6 t-\frac{x}{60}\right)\right]$
D $y=0.2 \sin \left[\pi\left(6 t-\frac{x}{60}\right)\right]$

Correct answer

C. $y=0.2 \sin \left[2 \pi\left(6 t-\frac{x}{60}\right)\right]$

Step-by-step solution

The general equation of wave travelling in

x

-direction is given as y=A \sin

\left[\frac{2 \pi}{\lambda}(

V t-x)\right] Where

A=0.2 \mathrm{~m}, v=360 \mathrm{~ms}^{-1}, \lambda=60 \mathrm{~m}\therefore

The equation becomes

\begin{aligned}& y=0.2 \sin \left[\frac{2 \pi}{60}(360 t-x)\right] \\ & y=0.2 \sin \left[2 \pi\left(6 t-\frac{x}{60}\right)\right] \end{aligned}

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