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NEET2008PhysicsWaves and SoundActual

Two points are located at a distance of 10 ~m and 15 ~m from the source of oscillation. The period of oscillation is 0.05 ~s and the velocity of the wave is 300 ~m / s . What is the phase difference between the oscillations of two points?

Options

  1. A3
  2. B2 3
  3. C6

Correct answer

B. 2 3

Step-by-step solution

Key Idea : Phase difference = 2 path difference Path difference between two points, x=15-10=5 ~m Time period, T=0.05 ~s frequency v= 1 T = 1 0.05 =20 ~Hz Velocity, y=300 ~m / s Wavelength, = v v = 300 20 =15 ~m Hence, phase difference aligned & = 2 x & = 2 15 5= 2 3 aligned

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