Each of the two strings of length 51.6 ~cm and 49.1 ~cm are tensioned separately by 20 ~N force. Mass per unit length of both the strings is same and equal to 1 ~g / m . When both the strings vibrate simultaneously the

Correct answer: C. 7 \ Deltav= V 2 _1 - V 2 _2 = V 2 [(1)/( _1)-(1)/( _2)] =(1)/(2) T μ (\ (1)/( _1)-(1)/( _2)\

NEET 2009

NEET 2009 · Physics · Waves and Sound

Each of the two strings of length 51.6 ~cm and 49.1 ~cm are...

Each of the two strings of length

51.6 \mathrm{~cm}

and

49.1 \mathrm{~cm}

are tensioned separately by

20 \mathrm{~N}

force. Mass per unit length of both the strings is same and equal to

1 \mathrm{~g} / \mathrm{m}

. When both the strings vibrate simultaneously the number of beats is :

C. 7

Deltav=\frac{\mathrm{V}}{2 \ell_1}-\frac{\mathrm{V}}{2 \ell_2}=\frac{\mathrm{V}}{2} \left[\frac{1}{\ell_1}-\frac{1}{\ell_2}\right] =\frac{1}{2} \sqrt{\frac{\mathrm{T}}{\mu}} \left(\

{\frac{1}{\ell_1}-\frac{1}{\ell_2}\right\}