NEET2009PhysicsWaves and SoundActual
Each of the two strings of length 51.6 ~cm and 49.1 ~cm are tensioned separately by 20 ~N force. Mass per unit length of both the strings is same and equal to 1 ~g / m . When both the strings vibrate simultaneously the number of beats is :
Options
- A3
- B5
- C7
- D8
Correct answer
C. 7
Step-by-step solution
v= V 2 ₁ - V 2 ₂ = V 2 [ 1 ₁ - 1 ₂ ] = 1 2 T 1 ₁ - 1 ₂