NEST2024PhysicsAtomic Physics
In a sequence of two consecutive steps, a hydrogen atom in its ground state absorbs two photons and finally reaches its n=7 excited state. The energy of the first incident photon is found to be 12.47 eV , with an error margin of 0.32 eV . The energy, in eV , of second absorbed photon is closest to
Options
- A0.57
- B1.45
- C0.81
- D3.40
Correct answer
A. 0.57
Step-by-step solution
No solution available.