NEST2016PhysicsElectrostatics
An electrostatic field line leaves at an angle from point charge q₁ , and connects with point charge -q₂ at an angle ( q₁ and q₂ are positive), as shown schematically in the figure. We have q₁=2 q₂ and =60^ . Then,
Options
- Aa test charge placed at the midpoint O will be in equilibrium
- B=90^
- Cthe magnitude of the electric field at a distance r far away from O (see figure) is q₂ / 4 _o r^2 .
- Dfor a negative test charge, the electrostatic potential energy is lower near q₁ as compared to that near q₂ .
Correct answer
D. for a negative test charge, the electrostatic potential energy is lower near q₁ as compared to that near q₂ .
Step-by-step solution
No solution available.