NEST2022PhysicsElectrostatics
A hollow thin-walled glass tube of length L , is open at one end while the other end is closed by a hollow thin-walled glass hemisphere of radius R . The axis of the tube is along the x -axis with the open end at the origin, as shown in the figure. A net positive charge Q is distributed uniformly over the entire surface with surface charge density . The magnitude of the electric field at O due to the hemisphere is /
Options
- AIf L=R , then the direction of electric field at O is - i .
- BThe surface charge density = Q 2 R(L+2 R)
- CAt a point x L, R , the magnitude of the electric field is proportional to 1 / x^2 .
- DWhen L= 3 R , the electric field at O is zero.
Correct answer
D. When L= 3 R , the electric field at O is zero.
Step-by-step solution
No solution available.