The equilibrium constants (K_ P 1 ) and (K_ P 2 ) for the reaction (X 2 Y ) and (Z P+Q ), respectively are in the ratio of (1: ) 9. If the degree of dissociation of (X ) and (Z ) be equal then the ratio of total pressure at these equilibria is:

Step-by-step solution

X ( g ) ⇌ 2Y ( g ) 1 0 At equilibrium 1 − x 2x Total no. of moles = 1 + x K p 1 = 2x 1+x .p 1 2 1 − x 1+x .p 1 = 4x 2 1 − x p 1 1+x = 4x 2 p 1 1 − x 2 Z ( g ) ⇌ P ( g ) +Q ( g ) 1 0 0 At equilibrium 1 − x x x Similarly, K p 2 = x 2 1 − x p 2 1+x = x 2 p 2 1 − x 2 ∴ K p1 K p2 = 1 9 So, 4   ×   p 1 p 2   =   1 9 ⇒ p 1 p 2   =   1 36