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NTA Abhyas 2020
Exam
NTA Abhyas
Year
2020
Subject
Chemistry
Chapter
Chemical Equilibrium

NTA Abhyas 2020 · Chemistry · Chemical Equilibrium

One of the reaction that takes place in producing steel from iron...

One of the reaction that takes place in producing steel from iron ore is the reduction of iron(II)\text{iron(II)} oxide by carbon monoxide to give iron metal and {\text{CO}_{2}.
\text{FeO}\left(\text{s}\right)\text{+}\text{CO}\left(\text{g}\right) ⇌ \text{Fe}\left(\text{s}\right)\text{+}{\text{CO}_{2} \left(\text{g}\right){\text{; K}_{P} \text{=}\text{0}\text{.265}\text{atm} at 1050K.\text{1050}\text{K}\text{.} What are the equilibrium partial pressures of CO\text{CO} and CO2C{O}_{2} respectively at 1050K\text{1050}\text{K} if the initial partial pressures are: Pco=1.4{P}_{co} = 1.4 atm and PCO2=0.80atm{P}_{C{O}_{2}} = 0.80atm ?One of the reaction that takes place in producing steel from iron ore is the reduction of iron(II) oxide by carbon

Options

  1. A[PCO]=1.739atmandPCO2=0.461atm\left[{P}_{CO}\right] = 1.739atmand{P}_{C{O}_{2}} = 0.461atm
  2. B[PCO]=17.39atmandPCO2=0.461atm\left[{P}_{CO}\right] = 17.39atmand{P}_{C{O}_{2}} = 0.461atm
  3. C[PCO]=1.79atmandPCO2=0.46atm\left[{P}_{CO}\right] = 1.79atmand{P}_{C{O}_{2}} = 0.46atm
  4. D[PCO]=2.739atmandPCO2=1.461atm\left[{P}_{CO}\right] = 2.739atmand{P}_{C{O}_{2}} = 1.461atm

Correct answer

A. [PCO]=1.739atmandPCO2=0.461atm\left[{P}_{CO}\right] = 1.739atmand{P}_{C{O}_{2}} = 0.461atm

Step-by-step solution

One of the reaction that takes place in producing steel from iron ore is the reduction of iron(II) oxide by carbon

KP=0.265=0.8−x1.4+x{K}_{P} = 0.265 = \dfrac{0.8 - x}{1.4 + x}
On solving, x=0.339\text{x}\text{=}\text{0}\text{.339}
∴[PCO]=1.739∴ \left[{P}_{CO}\right] = 1.739 atm and PCO2=0.461atm{P}_{C{O}_{2}} = 0.461atm
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