NTA Abhyas JEE Main2020ChemistryChemical EquilibriumPractice
One of the reaction that takes place in producing steel from iron ore is the reduction of iron(II) oxide by carbon monoxide to give iron metal and CO 2 . FeO s + CO g ⇌ Fe s + CO 2 g ; K P = 0 .265 atm at 1050 K . What are the equilibrium partial pressures of CO and C O 2 respectively at 1050 K if the initial partial pressures are: P c o = 1.4 atm and P C O 2 = 0.80 a t m ?
Options
- AP C O = 1.739 a t m a n d P C O 2 = 0.461 a t m
- BP C O = 17.39 a t m a n d P C O 2 = 0.461 a t m
- CP C O = 1.79 a t m a n d P C O 2 = 0.46 a t m
- DP C O = 2.739 a t m a n d P C O 2 = 1.461 a t m
Correct answer
A. P C O = 1.739 a t m a n d P C O 2 = 0.461 a t m
Step-by-step solution
K P = 0.265 = 0.8 - x 1.4 + x On solving, x = 0 .339 ∴ P C O = 1.739 atm and P C O 2 = 0.461 a t m