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1 mole of N 2 O 4 ( g ) at 300 K is kept in a closed container under 1 atm . It is heated to 600 K when 20% by mole of N 2 O 4 ( g ) decomposes to N O 2 ( g ) . The resultant pressure is

Options

  1. A1.2 atm
  2. B2.4 atm
  3. C2.0 atm
  4. D1.0 atm

Correct answer

B. 2.4 atm

Step-by-step solution

N 2 O 4 (g) ⇌ 2NO 2 (g) Initial   mole 1 0 At   equi . (1-0 .20)   mole 0 .40   mole n total = 1 .2 P total = n total RT V = 2 .4 atm as P 2 P 1 = n 2 T 2 n 1 T 1

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