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NTA Abhyas 2020
Exam
NTA Abhyas
Year
2020
Subject
Chemistry
Chapter
Chemical Equilibrium

NTA Abhyas 2020 · Chemistry · Chemical Equilibrium

N H _ 4 HS ( s ) ⇌ N H _ 3 ( g ) + H _ 2 S ( g ) The equilibrium...

NH4HS(s)⇌NH3(g)+H2S(g)N{H}_{4}HS ( s ) ⇌ N{H}_{3} ( g ) + {H}_{2}S ( g )
The equilibrium pressure at 25°C is 0.660 atm. What is Kp{K}_{p} for the reaction?

Options

  1. A0.109 (atm)2( atm{)}^{2}
  2. B0.218 (atm)2( atm{)}^{2}
  3. C1.89 (atm)2( atm{)}^{2}
  4. D2.18 (atm)2( atm{)}^{2}

Correct answer

A. 0.109 (atm)2( atm{)}^{2}

Step-by-step solution

{\text{NH}_{4} \text{HS}\left(\text{s}\right) ⇌ \mathop{{\text{NH}_{3} \left(\text{g}\right)}_{P} + \mathop{{H}_{2} \text{S}\left(\text{g}\right)}_{P}
Equilibrium pressure is 2P here
2P=0.6602P = 0.660
P=0.330P = 0.330
Kp=PNH3.PH2S{K}_{p} = {P}_{N{H}_{3}}. {P}_{{H}_{2}S}
=0.33×0.33=0.109(atm)2= 0.33 \times 0.33 = 0.109 ( atm{)}^{2}
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