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Hydrogen peroxide (H 2 O 2 ) decomposes according to the equation 2 H 2 O 2 ⇌ 2 H 2 O I + O 2 g From the following data at 2 5 ∘ C calculate the value of K p at 400 K for the above reaction, Δ H ∘ = - 1 9 6 · 0 KJ Δ S ∘ = 1 2 5 · 6 5 J/K . [Given: 10 0.15 = 1.41 ]

Options

  1. A0.14 x 10 32
  2. B0.14 x 10 -32
  3. C0.14 x 10 3
  4. D1.3 x 10 15

Correct answer

A. 0.14 x 10 32

Step-by-step solution

Δ G ∘ = + Δ H ∘ - T Δ S ∘ = - 1 9 6 0 0 0 - 4 0 0 1 2 5 · 6 5 = - 1 9 6 0 0 0 - 5 0 2 6 0 = - 2 4 6 2 6 0 J = - 2 · 3 0 3 × 8 · 3 1 4 × 4 0 0 log K p log K p = - 2 4 6 2 6 0 - 7 6 5 8 = 3 2 · 1 5 K p = Antilog 3 2 · 1 5 = 0.1 4 × 1 0 3 2

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