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What will be the expression of K p for the given reaction if the total pressure inside the vessel is P and degree of dissociation of the reactant is a? The reaction N 2 O 4 ⇄ 2 NO 2

Options

  1. A4 a 2 P 1 + a 2
  2. B4 a 2 P 1 - a 2
  3. Ca 2 P 1 - a 2
  4. Da 2 1 - a 2

Correct answer

B. 4 a 2 P 1 - a 2

Step-by-step solution

M o l e s a t t = 0 M o l e s a t e q u i l i b r i u m N 2 O 4 1 1 - a ⇌ 2 N O 2 0 2 a Total moles at equilibrium = 1 - a + 2 a = 1 + a P N 2 O 4 = ( 1 − a 1 + a ) P ; P NO 2 = ( 2 a 1 + a ) P K p = P N O 2 P N 2 O 4 = 2 a 1 + a 2 P 2 1 - a 1 + a P = 4 a 2 P 1 - a 2

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