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NTA Abhyas 2020
Exam
NTA Abhyas
Year
2020
Subject
Chemistry
Chapter
Chemical Equilibrium

NTA Abhyas 2020 · Chemistry · Chemical Equilibrium

Equivalent amounts of H _ 2 and I _ 2 are heated in a closed vessel...

Equivalent amounts of H2andI2{H}_{2}and{I}_{2} are heated in a closed vessel till equilibrium is obtained. If 80% of the hydrogen can be converted to HI,\text{HI,} the Kc{K}_{c} at this temperature is

Options

  1. A64
  2. B16
  3. C0.25
  4. D4

Correct answer

A. 64

Step-by-step solution

Let here be 1M each of H_{2} and I_{2} H2+I2⇌2HI1 and  and  and  and  and  and  and  and  and  and  and 1 and  and  and  and  and  and  and  and  and 0(1−0.8) and  and  and  and  and  and (1−0.8) and  and 2×0.8{H}_{2} + {I}_{2} ⇌ 2HI 1 \text{ and } \text{ and } \text{ and } \text{ and } \text{ and } \text{ and } \text{ and } \text{ and } \text{ and } \text{ and } \text{ and } 1 \text{ and } \text{ and } \text{ and } \text{ and } \text{ and } \text{ and } \text{ and } \text{ and } \text{ and } 0 (1-0.8) \text{ and } \text{ and } \text{ and } \text{ and } \text{ and } \text{ and } (1-0.8) \text{ and } \text{ and } 2 \times 0.8 =0.2 & & & & & & &=0.2& & & & & & &=1.6 Kc=[HI]2[H2][I2]=1.6×1.60.2×0.2Kc=64{K}_{c} \text{=}\dfrac{{\left[\text{HI}\right]}^{2}}{\left[{H}_{2}\right]\left[{I}_{2}\right]} \text{=}\dfrac{1.6 \times 1.6}{0.2 \times 0.2} {K}_{c} \text{=}\text{64}
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