Equivalent amounts of H 2 a n d I 2 are heated in a closed vessel till equilibrium is obtained. If 80% of the hydrogen can be converted to HI, the K c at this temperature is

Step-by-step solution

Let here be 1M each of H 2 and I 2 H 2 + I 2 ⇌ 2 H I 1 1 0 (1-0.8) (1-0.8) 2 × 0.8 =0.2 =0.2 =1.6 K c   =   HI 2 H 2 I 2  = 1.6 × 1.6 0.2 × 0.2 K c   =   64