Quantrex Quantrex AcademyJEE · NEET · NDA PYQs with solutions Open app
NTA Abhyas 2020
Exam
NTA Abhyas
Year
2020
Subject
Chemistry
Chapter
Chemical Equilibrium

NTA Abhyas 2020 · Chemistry · Chemical Equilibrium

K _ p for the reaction PC l _ 5 (g) ⇌ PC l _ 3 (g) + C l _ 2 (g) at...

Kp{K}_{p} for the reaction PCl5(g)⇌PCl3PC{l}_{5} \left(g\right) ⇌ PC{l}_{3}\left(g\right) + Cl2(g)C{l}_{2}\left(g\right) at {250oC\text{250}^{o} \text{C} is 0.82\text{0}\text{.82}.Calculate the degree of dissociation at given temperature under a pressure of 5atm\text{5}\text{atm}.What will be the degree of dissociation if the equilibrium pressure is 10atm\text{10}\text{atm} at same temperature.K _ p for the reaction PC l _ 5 (g) ⇌ PC l _ 3 (g) + C l _ 2 (g) at 250^ o C is 0.82 .Calculate the degree of

Options

  1. A27.5%
  2. B23%
  3. C35.5%
  4. D40%

Correct answer

A. 27.5%

Step-by-step solution

K _ p for the reaction PC l _ 5 (g) ⇌ PC l _ 3 (g) + C l _ 2 (g) at 250^ o C is 0.82 .Calculate the degree of

KP=(x1+x)P×(x1+x)P(1−x1+x)P{K}_{P} = \dfrac{\left(\dfrac{x}{1 + x}\right)P \times \left(\dfrac{x}{1 + x}\right)P}{\left(\dfrac{1 - x}{1 + x}\right)P}

KP=x21−x2P=0.82{K}_{P} = \dfrac{x^{2}}{1 - x^{2}}P = 0.82

x2=0.825.82x^{2} = \sqrt{\dfrac{0.82}{5.82}}

x=0.375x = 0.375

Now new pressure is 10

KP=y2×P1−y2{K}_{P} = \dfrac{y^{2} \times P}{1 - y^{2}} , 0.82=y21−y2×100.82 = \dfrac{y^{2}}{1 - y^{2}} \times 10

y=0.275y = 0.275 , y=27.5y = 27.5%
Practice Chemical Equilibrium on Quantrex Academy →

More from Chemical Equilibrium

Consider the following reactions in which all the reactants and products are present in… JEE Main 2026Solid carbon, CaO and CaCO _3 are mixed and allowed to attain equilibrium at T K.… JEE Main 2026In a closed flask at 600 K, one mole of X _2 Y _4 (g) attains equilibrium as given below… JEE Main 2026One mole each of He and A(g) are taken in a 10 L closed flask and heated to 400 K to… JEE Main 2026The reaction A(g) leftharpoons B(g) + C(g) was initiated with the amount ' a ' of A(g) .… JEE Main 2026The values of pressure equilibrium constant recorded at different temperatures for the… JEE Main 2026For the following reaction at 50° C and at 2 atm pressure, 2N_2O_5(g) leftharpoons… JEE Main 2026At T(K) , the equilibrium constant of A_2(g) + B_2(g) leftharpoons C(g) is 2.7 × 10^ -5 .… JEE Main 2026 Full Chemical Equilibrium list All NTA Abhyas JEE Main PYQs