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At a definite temperature, the equilibrium constant for a reaction, A + B ⇌ 2 C , was found to be 81. Starting with 1 mole A and 1 mole B, the mole fraction of C at equilibrium is :

Options

  1. A9 1 1
  2. B1 1 1
  3. C2 1 1
  4. D7 1 1

Correct answer

A. 9 1 1

Step-by-step solution

A + B ⇌ 2 C 1 1 0 1 - x 1 - x 2 x ∴ 8 1 = 4 x 2 1 - x 2 or 2 x 1 - x = 9 ∴ x = 9 1 1 Thus, A + B ⇌ 2 C 2 1 1 2 1 1 18 1 1 ( Total mole = 2 1 1 + 2 1 1 + 18 1 1 = 22 1 1 ) ∴ Mole fraction of C= 18 1 1 2 2 1 1 = 9 1 1

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