The equilibrium constant for the reaction H 2 O g + C O g ⇌ H 2 g + C O 2 g is 0.44 at 1260 K. The equilibrium constant for the reaction 2 H 2 g + 2 C O 2 g ⇌ 2 C O g + 2 H 2 O g at 1260 K is equal to

Step-by-step solution

2 H 2 ( g ) + 2 C O ( g ) ⇌ 2 C O ( g ) + 2 H 2 O ( g ) is obtained by reversing the reaction H 2 O ( g ) + C O ( g ) ⇌ H 2 ( g ) + C O 2 ( g ) and then multiplying it by the factor '2'. Hence the equilibrium constant ( K' ) for this reaction is given by K'= ( 1 K ) 2 = ( 1 0.44 ) 2 = 5.16