At 273 K and one atm, ‘ a ’ litre of N 2 O 4 decomposes to N O 2 as : N 2 O 4 g ⇌ 2 N O 2 g . To what extent has the decomposition proceeded when he original volume is 25% less then hat of existing volume? [Report your answer up to two decimal places.]

Step-by-step solution

∵ M o l e s ∝ v o l u m e a consant P and T I n i t i a l M o l e s M o l e s a t e q u i l i b r i u m N 2 O 4 a ( a - x ) ⇌ 2NO 2 ( g ) 0 2 x Given original volume = 75 100 of existing volume at equilibrium or initial moles = 75 100 ×moles at equilibrium ∴ a = 75 100 ( a + x ) or x = 25 75 a = 0 · 33.33 a ∴ D e g r e e o f d i s s o c i a t i o n , α = x a = 0.3333 a a = 0.3333 or 33.33 %